2[m-(2m+15)+15]=2(m+1)

Solution for 2[m-(2m+15)+15]=2(m+1) equation:

Simplifying
2[m + -1(2m + 15) + 15] = 2(m + 1)

Reorder the terms:
2[m + -1(15 + 2m) + 15] = 2(m + 1)
2[m + (15 * -1 + 2m * -1) + 15] = 2(m + 1)
2[m + (-15 + -2m) + 15] = 2(m + 1)

Reorder the terms:
2[-15 + 15 + m + -2m] = 2(m + 1)

Combine like terms: -15 + 15 = 0
2[0 + m + -2m] = 2(m + 1)
2[m + -2m] = 2(m + 1)

Combine like terms: m + -2m = -1m
2[-1m] = 2(m + 1)

Remove brackets around [-1m]
2 * -1m = 2(m + 1)

Multiply 2 * -1
-2m = 2(m + 1)

Reorder the terms:
-2m = 2(1 + m)
-2m = (1 * 2 + m * 2)
-2m = (2 + 2m)

Solving
-2m = 2 + 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
-2m + -2m = 2 + 2m + -2m

Combine like terms: -2m + -2m = -4m
-4m = 2 + 2m + -2m

Combine like terms: 2m + -2m = 0
-4m = 2 + 0
-4m = 2

Divide each side by '-4'.
m = -0.5

Simplifying
m = -0.5